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Cryptography Tutorials - Tutorial Addendum - Blank - DES Algorithm



 31 December 18:00   

    



    



    

(Continued from antecedent part...)

    



    

Permuted Best 2 - PC2:

    

 

    

14 17 11 24 1 5

    

3 28 15 6 21 10

    

23 19 12 4 26 8

    

16 7 27 20 13 2

    

41 52 31 37 47 55

    

30 40 51 45 33 48

    

44 49 39 56 34 53

    

46 42 50 36 29 32

    



    



    

Left accouterment (number of $.25 to rotate) - r1, r2, ..., r16:

    

 

    

r1 r2 r3 r4 r5 r6 r7 r8 r9 r10 r11 r12 r13 r14 r15 r16

    

1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1

    



    



    



    

DES Decryption Algorithm

    



    

The decryption algorithm of a block blank should be identical to encryption algorithm

    

step by move in about-face order. But for DES cipher, the encryption algorithm is so well

    

designed, that the decryption algorithm is identical to the encryption algorithm

    

step by move in the aforementioned order, alone with the subkeys activated in the about-face order.

    



    

DES decryption algorithm:

    

 

    

Input:

    

CC: 64 $.25 of blank text

    

k16, k15, ..., k1: 16 annular keys

    

IP: Antecedent permutation

    

FP: Final permutation

    

f(): Annular function

    



    

Output:

    

TT: 64 $.25 of bright text

    

Algorithm:

    

CC = IP(CC), applying antecedent permutation

    

(LL0, RR0) = CC , adding CC into two 32-bit parts

    

(LL1, RR1) = (RR0, LL0 ^ f(RR0, k16))

    

(LL2, RR2) = (RR1, LL1 ^ f(RR1, k15))

    

......

    

TT = (RR16, LL16), swapping the two parts

    

TT = FP(TT ), applying final permutation

    



    



    

Here is how to accept the decryption algorithm:

    

 

    

Let:

    

T: 64 $.25 of bright text

    

C: 64 $.25 of blank argument encrypted from T

    

CC: 64 $.25 of blank text

    

TT: 64 $.25 of bright argument decrypted from CC

    

If:

    

CC = C

    



    

Then:

    

TT = T

    

Prove:

    

CC = IP(CC) First move of decryption

    

= IP(C) Acceptance of CC = C

    

= IP(FP(C )) Endure move of encryption

    

= C IP is the changed about-face of FP

    

(LL0, RR0) = CC Initializing move in decryption

    

= C CC = C

    

= (R16, L16) Swapping move in encryption

    



    

(LL1, RR1) = (RR0, LL0 ^ f(RR0, k16))

    

First annular of decryption

    

= (L16, R16 ^ f(L16, k16))

    

Antecedent result

    

= (R15, (L15 ^ f(R15,k16)) ^ f(R15, k16))

    

(L16, R16) = (R15, L15 ^ f(R15, k16))

    

= (R15, L15) ^ about-face itself

    



    

......

    

(LL16, RR16) = (R0, L0)

    



    

TT = (RR16, LL16) Swapping in decryption

    

= (L0, R0) Antecedent result

    

= T Initializing move in encryption

    

TT = FP(TT ) Endure move in decryption

    

= FP(T ) Antecedent result

    

= FP(IP(T)) First move in encryption

    

= T FP is the changed about-face of IP

    



    



    

Conclusions:

    



        

  • DES is a 64-bit block cipher.

        



  •     

  • 16 annular keys are acquired from a individual 64-bit key.

        



  •     

  • Decryption algorithm is identical to the encryption algorithm except

        

    for the adjustment of the annular keys.

        



  •     



    



    

Now we understand how DES encryption algorithm works, let s try to apparatus it in Java.

    

See the next two chapters.

    



    



    



 


 algorithm, decryption, encryption, cipher, permutation, round, previous, result, swapping, identical, reverse, clear, , decryption algorithm, encryption algorithm, r15 l15, r15 k16, round keys, cipher text, previous result, rr16 ll16 swapping, tutorial notes cipher, tutorials tutorial notes, cryptography tutorials tutorial,

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